
Using reports for ACD planning
110 BCMS Operations
Example 3
The manager of a split in an ACD knows that calls average 75 seconds and that the split
receives 200 calls per hour. The manager wants most of the calls to be answered in less
than 40 seconds.
How many agents are required?
To answer this question, you must interpolate between all parameters-first, between delay
time and calls per hour to obtain the number of calls per hour for a 40-second delay. Under
the 30- and 45-second columns of 60 seconds average service time
on page 121 and 90
seconds average service time on page 123 you will find:
Interpolate between delay time and calls per hour in both tables to obtain calls per hour for
a 40-second delay.
60 seconds average service
time
75
seconds
90 seconds average service
time
Average speed of
answer
Average speed of
answer
Agents 30 40 45 Agents 30 40 45
5 186 ? 202 7 194 ? 205
? 200 ? 200
6 238 ? 257 8 231 ? 242
= number o f calls per hour
= y
0
+ (y
1
− y
0
)
x
1
− x
0
x − x
0
_ _______
= 186 + ( 202 − 186 )
45 − 30
40 − 30
_ _______
= 186 + ( 16 × 0. 666 )
= 196. 66
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